6[3-(4+4x)]=-8+2(1-14x)

Solution for 6[3-(4+4x)]=-8+2(1-14x) equation:

Simplifying
6[3 + -1(4 + 4x)] = -8 + 2(1 + -14x)
6[3 + (4 * -1 + 4x * -1)] = -8 + 2(1 + -14x)
6[3 + (-4 + -4x)] = -8 + 2(1 + -14x)

Combine like terms: 3 + -4 = -1
6[-1 + -4x] = -8 + 2(1 + -14x)
[-1 * 6 + -4x * 6] = -8 + 2(1 + -14x)
[-6 + -24x] = -8 + 2(1 + -14x)
-6 + -24x = -8 + (1 * 2 + -14x * 2)
-6 + -24x = -8 + (2 + -28x)

Combine like terms: -8 + 2 = -6
-6 + -24x = -6 + -28x

Add '6' to each side of the equation.
-6 + 6 + -24x = -6 + 6 + -28x

Combine like terms: -6 + 6 = 0
0 + -24x = -6 + 6 + -28x
-24x = -6 + 6 + -28x

Combine like terms: -6 + 6 = 0
-24x = 0 + -28x
-24x = -28x

Solving
-24x = -28x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '28x' to each side of the equation.
-24x + 28x = -28x + 28x

Combine like terms: -24x + 28x = 4x
4x = -28x + 28x

Combine like terms: -28x + 28x = 0
4x = 0

Divide each side by '4'.
x = 0

Simplifying
x = 0